8615. Outside the interval

Determine whether the number x is outside the interval [a; b]. The number x is outside the interval [a; b] if either x < a or x > b.

Input. Three integers x, a, b, each not exceeding 10⁹ in absolute value.

Output. Print “OUT” if the number x does not belong to the interval [a; b]. Otherwise, print “IN”.

Sample input 1	Sample output 1
7 2 7	IN
Sample input 2	Sample output 2
-5 1 1	OUT

SOLUTION

conditional statement

Algorithm analysis

Let’s combine the conditions x < a and x > b using the or (||) operator.

Algorithm implementation

Read the input data.

scanf("%d %d %d", &x, &a, &b);

Print the answer depending on whether the number x is outside or inside the interval [a; b].

if (x < a || x > b)

printf("OUT\n");

else

printf("IN\n");

Java implementation

import java.util.*;

public class Main

{

public static void main(String[] args)

{

Scanner con = new Scanner(System.in);

int x = con.nextInt();

int a = con.nextInt();

int b = con.nextInt();

if (x < a || x > b)

System.out.println("OUT");

else

System.out.println("IN");

con.close();

}

}

Python implementation

Read the input data.

x, a, b = map(int,input().split())

Print the answer depending on whether the number x is outside or inside the interval [a; b].

if x < a or x > b:

print("OUT")

else:

print("IN")